The equivalent resistance between A and B is | vedclass

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(C) $1$. Observe the circuit carefully. The two resistors of $2\ R$ at the bottom are in parallel. Their equivalent resistance is $R_{p1} = \frac{2\ R

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$R$

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(C) $1$. Observe the circuit carefully. The two resistors of $2\ R$ at the bottom are in parallel. Their equivalent resistance is $R_{p1} = \frac{2\ R 	imes 2\ R}{2\ R + 2\ R} = R$.$2$. This $R$ is in series with the resistor $R$ above it,giving $R + R = 2\ R$.$3$. This $2\ R$ is in parallel with the other $2\ R$ resistor connected to the same nodes. Their equivalent is $R_{p2} = \frac{2\ R 	imes 2\ R}{2\ R + 2\ R} = R$.$4$. This $R$ is in series with the top resistor $R$,giving $R + R = 2\ R$.$5$. Finally,this $2\ R$ is in parallel with the rightmost branch which consists of two $R$ resistors in series $(R + R = 2\ R)$.$6$. The total equivalent resistance $R_{eq}$ is $\frac{2\ R 	imes 2\ R}{2\ R + 2\ R} = R$.

The equivalent resistance between $A$ and $B$ is $:-$

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