The equivalent capacitance of the combination of capacitors shown in the figure between the points $P$ and $N$ is:

Five capacitors,each of capacity $C$,are connected as shown in the figure. The resultant capacity between $A$ and $B$ is $14 \mu F$. The capacity of each capacitor is (in $\mu F$)

Assertion : If three capacitors of capacitances $C_1 < C_2 < C_3$ are connected in parallel,then their equivalent capacitance $C_P > C_S$,where $C_S$ is the equivalent capacitance in series.
Reason : $\frac{1}{C_P} = \frac{1}{C_1} + \frac{1}{C_2} + \frac{1}{C_3}$

If there are three capacitors and a source with $e.m.f. \ V$,how should the three capacitors be connected to the source to maximize the stored energy?

In the given figure,the equivalent capacitance $C_{AB}$ is equal to ...... $C$.

Three capacitors of values $6\, \mu F, 3\, \mu F$ and $9\, \mu F$ are connected as shown in the figure. This combination is connected to a $10\, V$ battery. What is the potential difference across the plates of the $9\, \mu F$ capacitor in $V$?