The equilibrium constant $K_p$ for the following reaction at $191\,^{\circ}C$ is $1.24$. What is the value of $K_c$? $B_{(s)} + \frac{3}{2}F_{2(g)} \rightleftharpoons BF_{3(g)}$

  • A
    $6.7$
  • B
    $0.61$
  • C
    $8.3$
  • D
    $7.6$

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