The equation which is balanced and represents the correct product$(s)$ is:

$A$ mixture $X$ containing $0.02 \, mol$ of $[Co(NH_3)_5SO_4]Br$ and $0.02 \, mol$ of $[Co(NH_3)_5Br]SO_4$ is dissolved in water to make a $2 \, L$ solution.
$1 \, L \, of \, X + \text{Excess of } AgNO_3 \rightarrow Y \, mol \, of \, ppt.$
$1 \, L \, of \, X + \text{Excess of } BaCl_2 \rightarrow Z \, mol \, of \, ppt.$
Then $Y$ and $Z$ are respectively ...............

The volume (in $mL$) of $0.1 \ M$ $AgNO_3$ required for complete precipitation of chloride ions present in $30 \ mL$ of $0.01 \ M$ solution of $[Cr(H_2O)_5Cl]Cl_2$, as silver chloride is close to

In basic medium,the amount of $Ni^{2+}$ in a solution can be estimated with the dimethylglyoxime reagent. The correct statement$(s)$ about the reaction and the product is (are):

The volume (in $mL$) of $0.125\; M\; AgNO_{3}$ required to quantitatively precipitate chloride ions in $0.3\; g$ of $[Co(NH_{3})_{6}]Cl_{3}$ is (Given: $M_{[Co(NH_{3})_{6}]Cl_{3}} = 267.46\; g/mol$,$M_{AgNO_{3}} = 169.87\; g/mol$).

Match List-$I$ with List-$II$ and select the correct code:

List-$I$	List-$II$
$A$. Ziegler-Natta	$i$. $Fe_4[Fe(CN)_6]_3$
$B$. Brown ring complex	$ii$. $[Fe(H_2O)_5NO]SO_4$
$C$. Prussian Blue	$iii$. $Al(C_2H_5)_3 + TiCl_4$
$D$. Turnbull Blue	$iv$. $Fe_3[Fe(CN)_6]_2$

Correct code is: