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(C) The standard equation of a projectile trajectory is given by $y = x 	an 	heta - \frac{g}{2 u^2 \cos^2 	heta} x^2$. Comparing this with the give

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$18$

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(C) The standard equation of a projectile trajectory is given by $y = x 	an 	heta - \frac{g}{2 u^2 \cos^2 	heta} x^2$. Comparing this with the given equation $y = 10x - \left(\frac{5}{9}ight) x^2$,we get: $	an 	heta = 10$ $\frac{g}{2 u^2 \cos^2 	heta} = \frac{5}{9}$ Given $g = 10 \ m/s^2$,we substitute it into the second equation: $\frac{10}{2 u^2 \cos^2 	heta} = \frac{5}{9}$ $\frac{5}{u^2 \cos^2 	heta} = \frac{5}{9}$ $u^2 \cos^2 	heta = 9$ The range $R$ of a projectile is given by $R = \frac{2 u^2 \sin 	heta \cos 	heta}{g}$. We can rewrite this as $R = \frac{2 (u^2 \cos^2 	heta) 	an 	heta}{g}$. Substituting the known values: $R = \frac{2 	imes 9 	imes 10}{10} = 18 \ m$.

The equation of trajectory of a projectile is $y=10 x-\left(\frac{5}{9}\right) x^2$. If we assume $g=10 \ m/s^2$,the range of the projectile (in metres) is:

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