The equation of the radical axis of the pair | vedclass

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(C) The radical axis of two circles $S_1=0$ and $S_2=0$ is given by $S_1-S_2=0$.First,normalize the equations so the coefficients of $x^2$ and $y^2$ a

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$21x-68=0$

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(C) The radical axis of two circles $S_1=0$ and $S_2=0$ is given by $S_1-S_2=0$.First,normalize the equations so the coefficients of $x^2$ and $y^2$ are $1$.For $S_1: x^2+y^2-x+2y+\frac{18}{7}=0$For $S_2: x^2+y^2-\frac{7}{4}x+2y+5=0$Subtracting $S_2$ from $S_1$:$(x^2+y^2-x+2y+\frac{18}{7}) - (x^2+y^2-\frac{7}{4}x+2y+5) = 0$$-x + \frac{7}{4}x + \frac{18}{7} - 5 = 0$$\frac{3}{4}x + \frac{18-35}{7} = 0$$\frac{3}{4}x - \frac{17}{7} = 0$Multiplying by $28$:$21x - 68 = 0$

The equation of the radical axis of the pair of circles $7x^2+7y^2-7x+14y+18=0$ and $4x^2+4y^2-7x+8y+20=0$ is

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