The equation of the normal to the hyperbola f | vedclass

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(D) The equation of the hyperbola is $\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1$,where $a^2 = 16$ and $b^2 = 9$.The equation of the normal to the hyperbol

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$2x + \sqrt{3}y = 25$

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(D) The equation of the hyperbola is $\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1$,where $a^2 = 16$ and $b^2 = 9$.The equation of the normal to the hyperbola $\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1$ at the point $(x_1, y_1)$ is given by $\frac{a^2x}{x_1} + \frac{b^2y}{y_1} = a^2 + b^2$.Substituting $a^2 = 16$,$b^2 = 9$,$x_1 = 8$,and $y_1 = 3\sqrt{3}$:$\frac{16x}{8} + \frac{9y}{3\sqrt{3}} = 16 + 9$$2x + \frac{3y}{\sqrt{3}} = 25$$2x + \sqrt{3}y = 25$.

The equation of the normal to the hyperbola $\frac{x^2}{16} - \frac{y^2}{9} = 1$ at the point $(8, 3\sqrt{3})$ is

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