The equation of a straight line drawn through the focus of the parabola $y^2 = -4x$ at an angle of $120^\circ$ to the $x$-axis is:
- A$y + \sqrt{3}(x - 1) = 0$
- B$y - \sqrt{3}(x - 1) = 0$
- C$y + \sqrt{3}(x + 1) = 0$
- D$y - \sqrt{3}(x + 1) = 0$
Explore More
Similar Questions
If the segment intercepted by the parabola $y^2 = 4ax$ with the line $lx + my + n = 0$ subtends a right angle at the vertex,then
Medium
View SolutionFind the equation of the parabola that satisfies the following conditions: Focus $(6, 0)$,directrix $x = -6$.
Easy
View SolutionConsider the conic $C: 25(x - 1)^2 + 25(y + 1)^2 = (3x - 4y)^2$. If the curve $E$ is the locus of the point of intersection of perpendicular tangents to the conic $C$,then the minimum distance between the curve $E$ and the point $(2, -1)$ is:
The shortest distance between the line $x-y=1$ and the curve $x^{2}=2y$ is .... .
DifficultJEE MAIN 2021
View SolutionThe angle of intersection between the curves $y^2 = 4x$ and $x^2 = 32y$ at the point $(16, 8)$ is:
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo