The equation 4x^2 - 24xy + 11y^2 = 0 represen | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given equation is a homogeneous second-degree equation of the form $ax^2 + 2hxy + by^2 = 0$.Comparing $4x^2 - 24xy + 11y^2 = 0$ with the gener

Vedclass · Accepted Answer

Two lines through the origin

Vedclass · Answer

(C) The given equation is a homogeneous second-degree equation of the form $ax^2 + 2hxy + by^2 = 0$.Comparing $4x^2 - 24xy + 11y^2 = 0$ with the general form,we have $a = 4$,$2h = -24$,and $b = 11$.Since the equation is homogeneous and has no constant term,it represents a pair of straight lines passing through the origin.To factorize: $4x^2 - 22xy - 2xy + 11y^2 = 0$$2x(2x - 11y) - y(2x - 11y) = 0$$(2x - y)(2x - 11y) = 0$Thus,the lines are $2x - y = 0$ and $2x - 11y = 0$,both of which pass through the origin $(0, 0)$.

The equation $4x^2 - 24xy + 11y^2 = 0$ represents

Similar Questions

Which of the following regulates blood pressure and heart rate?

In the following circuit,find $I_1$ and $I_2$.

Let $A = \{2, 4, 6, 8\}$. $A$ relation $R$ on $A$ is defined by $R = \{(2, 4), (4, 2), (4, 6), (6, 4)\}$. Then $R$ is

If $\Delta = a^2 - (b - c)^2$ is the area of the $\triangle ABC$,then $\tan A$ is equal to

Phytochrome is involved in:

Vedclass Test Series

Exam Paper Generator

Online Exam Module