The enthalpy of the reaction,$H_{2(g)} + \frac{1}{2}O_{2(g)} \to H_2O_{(g)}$ is $\Delta H_1$ and that of $H_{2(g)} + \frac{1}{2}O_{2(g)} \to H_2O_{(l)}$ is $\Delta H_2$,then:

  • A
    $\Delta H_1 > \Delta H_2$
  • B
    $\Delta H_1 + \Delta H_2 = 0$
  • C
    $\Delta H_1 < \Delta H_2$
  • D
    $\Delta H_1 = \Delta H_2$

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