The enolic form of ethyl acetoacetate,as show | vedclass

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(C) The chemical formula of the enolic form of ethyl acetoacetate is $CH_3-C(OH)=CH-COOCH_2CH_3$.Counting the bonds:$1$. Sigma $(\sigma)$ bonds: There

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$18$ sigma bonds and $2$ pi-bonds

Vedclass · Answer

(C) The chemical formula of the enolic form of ethyl acetoacetate is $CH_3-C(OH)=CH-COOCH_2CH_3$.Counting the bonds:$1$. Sigma $(\sigma)$ bonds: There are $18$ sigma bonds in the molecule.$2$. Pi $(\pi)$ bonds: There are $2$ pi bonds (one in the $C=C$ double bond and one in the $C=O$ double bond).Therefore,the correct answer is $18$ sigma bonds and $2$ pi-bonds.

The enolic form of ethyl acetoacetate,as shown below,has:

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