The energy stored in the capacitor is

$A$ parallel plate capacitor of capacitance $1 \ \mu F$ is charged to a potential difference of $20 \ V$. The distance between the plates is $1 \ \mu m$. The energy density between the plates of the capacitor is:

$A$ capacitor of capacitance $5 \mu F$ is charged by a battery of emf $10 \text{ V}$. At an instant of time,the potential difference across the capacitor is $4 \text{ V}$ and the time rate of change of potential difference across the capacitor is $0.6 \text{ Vs}^{-1}$. Then,the time rate at which energy is stored in the capacitor at that instant is:

$A$ fully charged capacitor has a capacitance $C$. It is discharged through a small coil of resistance wire,embedded in a block of specific heat $s$ and mass $m$ under thermally isolated conditions. If the temperature of the block is raised by $\Delta T$,the potential difference $V$ across the capacitor initially is

Two capacitors,one of capacity $\frac{C}{2}$ and the other of capacity $C$,are connected to a battery of voltage $V$ as shown. The work done in charging both the capacitors fully is

$A$ $6\,\mu F$ capacitor is charged from $10\,V$ to $20\,V$. The increase in energy will be: