The energy released when $\frac{7}{17.13} \text{ kg}$ of $^7_3\text{Li}$ is converted into $^4_2\text{He}$ by proton bombardment is $\alpha \times 10^{32} \text{ eV}$. The value of $\alpha$ is . . . . . . . (Nearest integer) (Mass of $^7_3\text{Li} = 7.0183 \text{ u}$,mass of $^4_2\text{He} = 4.004 \text{ u}$,mass of proton $= 1.008 \text{ u}$,$1 \text{ u} = 931 \text{ MeV/c}^2$,and Avogadro number $N_A = 6.0 \times 10^{23} \text{ mol}^{-1}$)

• A
  $5$
• B
  $6$
• C
  $8$
• D
  $10$