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(B) The energy $E$ of a photon is related to its wavelength $\lambda$ by the formula $\lambda = \frac{hc}{E}$.Given,$E = 15\, keV = 15 	imes 10^3\, e

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$X$-rays

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(B) The energy $E$ of a photon is related to its wavelength $\lambda$ by the formula $\lambda = \frac{hc}{E}$.Given,$E = 15\, keV = 15 	imes 10^3\, eV$.The value of $hc$ is approximately $1240\, eV\, nm$.Substituting these values,we get $\lambda = \frac{1240\, eV\, nm}{15 	imes 10^3\, eV} \approx 0.083\, nm$.The wavelength range for $X$-rays typically spans from $1\, nm$ to $10^{-3}\, nm$.Since $0.083\, nm$ falls within this range,the electromagnetic waves belong to the $X$-ray part of the spectrum.

List-$I$ (Electromagnetic wave)	List-$II$ (Production)
$A$. Microwave	$I$. Electrons in atoms emit light when they move from a higher energy level to a lower energy level
$B$. Visible light	$II$. Radioactive decay of nucleus
$C$. Gamma rays	$III$. Vibration of atoms and molecules
$D$. Infra-red rays	$IV$. Klystron valve or magnetron valve

The energy of the electromagnetic waves is of the order of $15\, keV$. To which part of the spectrum does it belong?

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