(D) The energy of an orbit in a hydrogen atom is given by the formula $E_n = \frac{-1312}{n^2} \ kJ \ mol^{-1}$.Given,for the second orbit $(n=2)$,$E_

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(D) The energy of an orbit in a hydrogen atom is given by the formula $E_n = \frac{-1312}{n^2} \ kJ \ mol^{-1}$.Given,for the second orbit $(n=2)$,$E_2 = -328 \ kJ \ mol^{-1}$.For the fourth orbit $(n=4)$,the energy $E_4$ is related to $E_2$ by the ratio $\frac{E_4}{E_2} = \frac{n_2^2}{n_4^2} = \frac{2^2}{4^2} = \frac{4}{16} = \frac{1}{4}$.Therefore,$E_4 = \frac{E_2}{4} = \frac{-328}{4} = -82 \ kJ \ mol^{-1}$.

Class 11 Chemistry Structure of Atom Atomic models and Planck's quantum theory

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The energy of the second Bohr orbit of the hydrogen atom is $-328 \ kJ \ mol^{-1}$. Hence,the energy of the fourth Bohr orbit would be .............. $kJ \ mol^{-1}$.

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A
$-41$
B
$-1312$
C
$-164$
D
$-82$

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Structure of Atom

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Atomic models and Planck's quantum theory

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The energy of the second Bohr orbit of the hydrogen atom is $-328 \ kJ \ mol^{-1}$. Hence,the energy of the fourth Bohr orbit would be .............. $kJ \ mol^{-1}$.

Similar Questions

If $P.E.$ of $3^{rd}$ shell is $-20 \ eV/atom$,then find the $I.P.$ of the $3^{rd}$ shell of that element.

Explain Rutherford's nuclear model of the atom.

Henry Moseley studied the characteristic $X$-ray spectra of elements. The graph which represents his observation correctly is: (Given $\nu =$ frequency of $X$-ray emitted; $Z =$ atomic number)

The ionization energy of a hydrogen atom is $13.6 \, eV$. What is the energy required (in $eV$) to excite the electron from the ground state to the first excited state?

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