The energy of an electron in the $n^{\text{th}}$ Bohr orbit of an $H$-atom is given by:
- A$\frac{-13.6}{n^2} \text{ eV}$
- B$\frac{-13.6}{n} \text{ eV}$
- C$\frac{-13.6}{n^4} \text{ eV}$
- D$\frac{-13.6}{n^3} \text{ eV}$
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