The energy of a mole of light quanta is 72 k | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The photosynthetic equation is $6CO_2 + 12H_2O + 	ext{Light Energy} ightarrow C_6H_{12}O_6 + 6O_2 + 6H_2O$. To synthesize $1 \ mole$ of glucose

Vedclass · Accepted Answer

$1968 \ to \ 3456 \ kcal$

Vedclass · Answer

(B) The photosynthetic equation is $6CO_2 + 12H_2O + 	ext{Light Energy} ightarrow C_6H_{12}O_6 + 6O_2 + 6H_2O$. To synthesize $1 \ mole$ of glucose,$686 \ kcal$ of energy is stored in the chemical bonds. Photosynthesis is not $100\%$ efficient. According to the quantum requirement,$8 \ quanta$ are required to evolve $1 \ mole$ of $O_2$. For $1 \ mole$ of glucose,$6 \ moles$ of $O_2$ are evolved,thus requiring $6 	imes 8 = 48 \ quanta$ (moles of photons). In the blue region $(400 \ nm)$,$1 \ mole$ of quanta provides $72 \ kcal$. Total energy required = $48 	imes 72 = 3456 \ kcal$. In the red region $(700 \ nm)$,$1 \ mole$ of quanta provides $41 \ kcal$. Total energy required = $48 	imes 41 = 1968 \ kcal$. Thus,the range of energy required is $1968 \ to \ 3456 \ kcal$.

The energy of a mole of light quanta is $72 \ kcal$ in the blue region at $400 \ nm$ and $41 \ kcal$ in the red region at $700 \ nm$. How much light energy would be required under standard conditions to make $1 \ mole$ of glucose costing $686 \ kcal$?

Similar Questions

Which of the following factors is essential for photosynthesis?

Which of the following pairs is incorrect?

Choose the correct sentence$(s)$ from the following:
$(i).$ In $C_4$ plants,the first $CO_2$ acceptor is $PEP$.
$(ii).$ Light energy is absorbed by $PS-II$ at $680 \ nm$ in the process of photosynthesis.
$(iii).$ The $P_{680}$ chlorophyll system is present in $PS-I$.

The first stable product of the Calvin cycle and the Hatch-Slack cycle are ......... respectively.

Which would do maximum harm to a tree?

Vedclass Test Series

Exam Paper Generator

Online Exam Module