The energy of a gas per litre is 300 J. Then | vedclass

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(D) The energy density $E$ is given as $300 \ J/litre$.Since $1 \ litre = 10^{-3} \ m^3$,the energy density in $SI$ units is $E = \frac{300 \ J}{10^{-

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$2 	imes 10^5 \ N/m^2$

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(D) The energy density $E$ is given as $300 \ J/litre$.Since $1 \ litre = 10^{-3} \ m^3$,the energy density in $SI$ units is $E = \frac{300 \ J}{10^{-3} \ m^3} = 300 	imes 10^3 \ J/m^3$.For an ideal gas,the pressure $P$ is related to the energy density $E$ by the formula $P = \frac{2}{3}E$.Substituting the value of $E$:$P = \frac{2}{3} 	imes (300 	imes 10^3) \ N/m^2$.$P = 200 	imes 10^3 \ N/m^2 = 2 	imes 10^5 \ N/m^2$.

The energy of a gas per litre is $300 \ J$. Then its pressure will be:

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