The energy gap of a semiconductor is 1.10 eV | vedclass

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Question

(B) The energy gap $E_g$ is related to the wavelength $\lambda$ by the formula $E_g = \frac{hc}{\lambda}$.To find the maximum wavelength $\lambda$ for

Vedclass · Accepted Answer

$11284$

Vedclass · Answer

(B) The energy gap $E_g$ is related to the wavelength $\lambda$ by the formula $E_g = \frac{hc}{\lambda}$.To find the maximum wavelength $\lambda$ for absorption, we rearrange the formula: $\lambda = \frac{hc}{E_g}$.Given $h = 6.63 	imes 10^{-34} \ J \cdot s$, $c = 3 	imes 10^8 \ m/s$, and $E_g = 1.10 \ eV = 1.10 	imes 1.6 	imes 10^{-19} \ J$.Substituting the values: $\lambda = \frac{6.63 	imes 10^{-34} 	imes 3 	imes 10^8}{1.10 	imes 1.6 	imes 10^{-19}} \ m$.$\lambda = \frac{19.89 	imes 10^{-26}}{1.76 	imes 10^{-19}} \ m \approx 11.30 	imes 10^{-7} \ m$.Converting to $\mathring{A}$s $(\mathring{A})$, where $1 \ m = 10^{10} \ \mathring{A}$:$\lambda \approx 11.30 	imes 10^{-7} 	imes 10^{10} \ \mathring{A} = 11300 \ \mathring{A}$.Comparing with the given options, the closest value is $11284 \ \mathring{A}$.

The energy gap of a semiconductor is $1.10 \ eV$. The maximum wavelength in $\mathring{A}$ at which it starts energy absorption will be (approximately):

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