The energy distribution E with the wavelength | vedclass

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(A) According to Wien's displacement law,$\lambda_m \propto \frac{1}{T}$,where $\lambda_m$ is the wavelength corresponding to the maximum energy emiss

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Shift towards left and become higher

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(A) According to Wien's displacement law,$\lambda_m \propto \frac{1}{T}$,where $\lambda_m$ is the wavelength corresponding to the maximum energy emission.As the temperature $T$ increases,the wavelength $\lambda_m$ corresponding to the peak of the $E - \lambda$ curve decreases,meaning the peak shifts towards the left (shorter wavelengths).Additionally,according to the Stefan-Boltzmann law,the total energy emitted per unit area per unit time is proportional to $T^4$. Therefore,as the temperature increases,the total area under the curve increases,and the peak of the curve becomes higher.Thus,the maxima will shift towards the left and become higher.

The energy distribution $E$ with the wavelength $\lambda$ for black body radiation at temperature $T \ K$ is shown in the figure. As the temperature is increased,the maxima will:

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