The energies of activation for forward and re | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$(A)$ The enthalpy change of a reaction $(\Delta H)$ is defined as the difference between the activation energy of the forward reaction $(E_{af})$ and

Vedclass · Accepted Answer

$-20$

Vedclass · Answer

$(A)$ The enthalpy change of a reaction $(\Delta H)$ is defined as the difference between the activation energy of the forward reaction $(E_{af})$ and the activation energy of the reverse reaction $(E_{ab})$.$\Delta H = E_{af} - E_{ab} = 180 \, kJ \, mol^{-1} - 200 \, kJ \, mol^{-1} = -20 \, kJ \, mol^{-1}$.$A$ catalyst provides an alternative reaction pathway with lower activation energy, but it does not change the energy of the reactants or the products.Since $\Delta H$ is a state function, it depends only on the initial and final states of the system.Therefore, the enthalpy change of the reaction remains unchanged in the presence of a catalyst, which is $-20 \, kJ \, mol^{-1}$.

Similar Questions

In a reaction,the rate of reaction doubles with a $10^\circ C$ rise in temperature. If the temperature is increased from $10^\circ C$ to $100^\circ C$,by how many times will the rate of reaction increase?

The rate of a chemical reaction doubles for every $10^\circ \text{C}$ rise in temperature. If the temperature is increased by $50^\circ \text{C}$,the rate of reaction will increase by a factor of ........

According to Arrhenius theory,the activation energy is

For the reaction $A + B \rightarrow C + D$,$\Delta H = -20 \ kJ \ mol^{-1}$. The activation energy for the forward reaction is $85 \ kJ \ mol^{-1}$. The activation energy for the reverse reaction is ......... $kJ \ mol^{-1}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module