The ends of a rope are held by two men who pull on it with equal and opposite forces of magnitude $F$ each. Then the tension in the rope is

The pulleys and strings shown in the figure are smooth and of negligible mass. For the system to remain in equilibrium,the angle $\theta$ should be:

$A$ block of mass $M$ is pulled along a horizontal frictionless surface by a rope of mass $M/2$. If a force $2Mg$ is applied at one end of the rope,the force which the rope exerts on the block is -

Consider a body of mass $3\,kg$ at rest on a smooth horizontal table. This body is connected by a light string,which passes over a smooth pulley at the edge of the table,to another body of mass $2\,kg$ hanging freely. This $2\,kg$ mass is released from rest. Now consider the following statements:
$(A)$ The masses remain at rest.
$(B)$ The $3\,kg$ mass moves uniformly while the $2\,kg$ mass moves with acceleration $\frac{2}{5}g\,m/s^2$.
$(C)$ Both bodies move with acceleration $\frac{2}{5}g\,m/s^2$.
$(D)$ The tension in the string near the first body is more than that near the second body.
$(E)$ The tension in the string is $\frac{6g}{5}\,N$.
Then the correct statements are:

When the system is allowed to fall freely,the tension in the string between the $10 \, kg$ and $5 \, kg$ masses is .......... $N$.

$A$ $2 \, kg$ block is lying on a smooth table and is connected to a body of mass $1 \, kg$ by a string passing over a pulley. The $1 \, kg$ mass is hanging vertically. Find the acceleration of the block and the tension in the string.