The end product of the $4n$ series is:

  • A
    $_{82}Pb^{208}$
  • B
    $_{82}Pb^{207}$
  • C
    $_{82}Pb^{209}$
  • D
    $_{83}Bi^{204}$

Explore More

Similar Questions

$_{90}Th^{228}$ emits four alpha and one beta particles. The number of neutrons in the daughter element is:

$^{14}C$ is

If radium and chlorine combine to form radium chloride,the compound would be

What is $X$ in the following nuclear reaction?
$_{7}N^{14} + _{1}H^{1} \xrightarrow{} _{8}O^{15} + X$

Uranium $_{92}U^{235}$ on bombardment with slow neutrons produces:

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo