The electrophile involved in the reaction shown below is:
$C_6H_5OH + CHCl_3 + NaOH \rightarrow C_6H_4(ONa)CHO$
$C_6H_5OH + CHCl_3 + NaOH \rightarrow C_6H_4(ONa)CHO$
- Adichlorocarbene $(:CCl_2)$
- Btrichloromethyl anion $(\mathop{C}\limits^{\ominus}Cl_3)$
- Cformyl cation $(\mathop{C}\limits^{\oplus}HO)$
- Ddichloromethyl cation $(\mathop{C}\limits^{+}HCl_2)$
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Similar Questions
The correct order of acid strength of the following compounds is:
$A$. Phenol
$B$. $p$-Cresol
$C$. $m$-Nitrophenol
$D$. $p$-Nitrophenol
$A$. Phenol
$B$. $p$-Cresol
$C$. $m$-Nitrophenol
$D$. $p$-Nitrophenol
Medium
View SolutionThe acidity of the following compounds follows the order:
$I$: Phenol
$II$: $p$-Methoxyphenol
$III$: $p$-Nitrophenol
$IV$: $m$-Nitrophenol
$I$: Phenol
$II$: $p$-Methoxyphenol
$III$: $p$-Nitrophenol
$IV$: $m$-Nitrophenol
MediumKVPY 2020
View Solution$C_6H_5OH + ClCOCH_3 \xrightarrow{\text{aq. } NaOH} C_6H_5OCOCH_3$ is an example of
Difficult
View SolutionThe increasing order of the rate of reaction with $Br_2 / AlCl_3$ is:
Medium
View SolutionAssertion: Phenol undergoes Kolbe reaction,ethanol does not.
Reason: Phenoxide ion is more basic than ethoxide ion.
Reason: Phenoxide ion is more basic than ethoxide ion.
DifficultAIIMS 2015
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