The electronic configurations of bivalent eur | vedclass

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(B) The atomic number of $Eu$ is $63$. The electronic configuration of $Eu$ is $[Xe] 4f^{7} 6s^{2}$.For $Eu^{2+}$,two electrons are removed from the $

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$[Xe] 4f^{7}$ and $[Xe] 4f^{1}$

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(B) The atomic number of $Eu$ is $63$. The electronic configuration of $Eu$ is $[Xe] 4f^{7} 6s^{2}$.For $Eu^{2+}$,two electrons are removed from the $6s$ orbital,resulting in $[Xe] 4f^{7}$.The atomic number of $Ce$ is $58$. The electronic configuration of $Ce$ is $[Xe] 4f^{1} 5d^{1} 6s^{2}$.For $Ce^{3+}$,three electrons are removed (two from $6s$ and one from $5d$),resulting in $[Xe] 4f^{1}$.

The electronic configurations of bivalent europium and trivalent cerium are
(atomic number : $Xe=54, Ce=58, Eu=63$ )

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The electronic configurations of bivalent europium and trivalent cerium are(atomic number : $Xe=54, Ce=58, Eu=63$ )