The electronic configurations of four elements are given in brackets:
$L(1s^2, 2s^2\ 2p^1);$ $M(1s^2, 2s^2\ 2p^5)$
$Q(1s^2, 2s^2\ 2p^6, 3s^1);$ $R(1s^2, 2s^2\ 2p^2)$
The element that would most readily form a diatomic molecule is:

  • A
    $Q$
  • B
    $M$
  • C
    $R$
  • D
    $L$

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Find the number of unpaired electrons for copper in ground state configuration.

Give the order of energy of orbitals in a multi-electron atom.

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$A$: No two electrons in an atom can have the same set of all four quantum numbers.
$R$: Two electrons in an atom can exist in the same shell,subshell,or orbital only if they have opposite spins.

For $n = 3$,what is the total number of orbitals and electrons present?

Which pair of atoms or ions will have the same electronic configuration?

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