The electronic configuration of Curium (Atomic number $96$) is

  • A
    $[Rn]\, 5f^3\, 6d^5\, 7s^2$
  • B
    $[Rn]\, 5f^7\, 6d^2\, 7s^1$
  • C
    $[Rn]\, 5f^7\, 6d^1\, 7s^2$
  • D
    $[Rn]\, 5f^8\, 6d^6\, 7s^2$

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Similar Questions

Although $(+3)$ oxidation state is the characteristic oxidation state of lanthanoids,cerium shows $(+4)$ oxidation state also. Why?

Which of the following is responsible for the lanthanoid contraction?

Given below are two statements:
Statement $I$: In the Lanthanoids,the formation of $Ce^{+4}$ is favoured by its noble gas configuration.
Statement $II$: $Ce^{+4}$ is a strong oxidant reverting to the common $+3$ state.
In the light of the above statements,choose the most appropriate answer from the options given below:

Identify the correct statements from the following :
$I$. The ionic radius of $Pr^{3+}, Dy^{3+}$ and $Sm^{3+}$ follow the order,$Sm^{3+} > Pr^{3+} > Dy^{3+}$.
$II$. $Eu^{2+}$ acts as a strong reducing agent.
$III$. $Pu$ exhibits $+7$ oxidation state.

What is the composition of metals in pyrophoric mischmetal?

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