The electronic configuration of an element wi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The difference between the $1^{st}$ and $2^{nd}$ ionisation energies is largest when the removal of the second electron requires breaking a stable

Vedclass · Accepted Answer

$1s^{2} 2s^{2} 2p^{6}$

Vedclass · Answer

(A) The difference between the $1^{st}$ and $2^{nd}$ ionisation energies is largest when the removal of the second electron requires breaking a stable,fully-filled shell or subshell configuration.						Electronic configuration			Element/Group							$1s^{2} 2s^{2} 2p^{6}$			Neon (Group $18$)							$1s^{2} 2s^{2} 2p^{6} 3s^{1}$			Sodium (Group $1$)							$1s^{2} 2s^{2} 2p^{6} 3s^{2}$			Magnesium (Group $2$)							$1s^{2} 2s^{2} 2p^{1}$			Boron (Group $13$)			For $1s^{2} 2s^{2} 2p^{6}$ (Neon),the $1^{st}$ ionisation energy is very high due to its stable noble gas configuration. However,the $2^{nd}$ ionisation energy is significantly higher because it involves removing an electron from a stable $2p^{6}$ shell,which is extremely difficult. Thus,the jump between $IE_1$ and $IE_2$ is largest for this configuration.

The electronic configuration of an element with the largest difference between the $1^{st}$ and $2^{nd}$ ionisation energies is

Similar Questions

The incorrect order of $1^{st}$ $IP$ of the elements is

Which of the following statements is correct about ionization potential?

The correct increasing order of ionisation enthalpy of $He, Li^{+}, Be^{2+}$ is

Explain why there is a phenomenal decrease in ionisation enthalpy from carbon to silicon?

Of the following isoelectronic ions,the one which has the lowest ionisation potential is

Vedclass Test Series

Exam Paper Generator

Online Exam Module