The electronegativity of the following elemen | vedclass

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(C) The electronegativity values (Pauling scale) for the given elements are approximately: $Si (1.90) < P (2.19) < C (2.55) < N (3.04)$.In the periodi

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$Si, P, C, N$

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(C) The electronegativity values (Pauling scale) for the given elements are approximately: $Si (1.90) In the periodic table,electronegativity increases from left to right across a period and decreases down a group.Comparing the elements: $Si$ and $P$ are in the $3^{rd}$ period,while $C$ and $N$ are in the $2^{nd}$ period.Since $Si$ and $P$ are below $C$ and $N$,they have lower electronegativity values.Within the same period,electronegativity increases from left to right ($Si Therefore,the correct order is $Si < P < C < N$.

The electronegativity of the following elements increases in the order:

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