The electric field part of an electromagnetic | vedclass

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(B) The given electric field is $E_y = E_0 \cos(\omega t - kx)$.Comparing this with the given equation $E_y = 2.5 \cos[(2\pi 	imes 10^6)t - (\pi 	im

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moving along $x$ direction with frequency $10^6 	ext{ Hz}$ and wavelength $200 	ext{ m}$

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(B) The given electric field is $E_y = E_0 \cos(\omega t - kx)$.Comparing this with the given equation $E_y = 2.5 \cos[(2\pi 	imes 10^6)t - (\pi 	imes 10^{-2})x]$,we identify the angular frequency $\omega = 2\pi 	imes 10^6 	ext{ rad/s}$ and the wave number $k = \pi 	imes 10^{-2} 	ext{ rad/m}$.Since the term inside the cosine is $(\omega t - kx)$,the wave is propagating in the positive $x$-direction.The frequency $f$ is given by $\omega = 2\pi f$,so $f = \frac{2\pi 	imes 10^6}{2\pi} = 10^6 	ext{ Hz}$.The wavelength $\lambda$ is given by $k = \frac{2\pi}{\lambda}$,so $\lambda = \frac{2\pi}{k} = \frac{2\pi}{\pi 	imes 10^{-2}} = 2 	imes 10^2 = 200 	ext{ m}$.Thus,the wave is moving along the $x$-direction with a frequency of $10^6 	ext{ Hz}$ and a wavelength of $200 	ext{ m}$.

The electric field part of an electromagnetic wave in a medium is represented by $E_x=0, E_y=2.5 \frac{N}{C} \cos \left[ (2\pi \times 10^6 \frac{rad}{s})t - (\pi \times 10^{-2} \frac{rad}{m})x \right]$,and $E_z=0$. The wave is

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