The electric field for an electromagnetic wav | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given electric field equation is $E = \hat{i} 30 \cos (kz - 5 	imes 10^8 t)$.The standard form of a traveling electromagnetic wave is $E = E_

Vedclass · Accepted Answer

$1.66 \ rad \ m^{-1}$

Vedclass · Answer

(C) The given electric field equation is $E = \hat{i} 30 \cos (kz - 5 	imes 10^8 t)$.The standard form of a traveling electromagnetic wave is $E = E_0 \cos (kz - \omega t)$.Comparing the given equation with the standard form,we get the angular frequency $\omega = 5 	imes 10^8 \ rad/s$.The relationship between the speed of light $c$,angular frequency $\omega$,and wave vector $k$ is given by $c = \frac{\omega}{k}$.Rearranging for $k$,we get $k = \frac{\omega}{c}$.Substituting the given values,$k = \frac{5 	imes 10^8 \ rad/s}{3 	imes 10^8 \ m/s} = \frac{5}{3} \ rad/m$.Therefore,$k \approx 1.66 \ rad/m$.

The electric field for an electromagnetic wave in free space is $E = \hat{i} 30 \cos (kz - 5 \times 10^8 t)$,where the magnitude of $E$ is in $V/m$. The magnitude of the wave vector $k$ is (velocity of $EM$ wave in free space $= 3 \times 10^8 \ m/s$).

Similar Questions

Identify the correct order in which the covalent radius of the following elements increases: $(I)$ $Ti$,$(II)$ $Ca$,$(III)$ $Sc$.

What is the volume (in litres) of oxygen at $STP$ required for complete combustion of $32 \ g$ of $CH_4$ ? (Molecular weight of $CH_4$ is $16$ )

$A$ gas formed by the action of alcoholic $KOH$ on ethyl iodide,decolourises alkaline $KMnO_4$. The gas is

For the parabola $y^2+6y-2x+5=0$:
$(I)$ The vertex is $(-2,-3)$
$(II)$ The directrix is $y+3=0$
Which of the following is correct?

Two particles which are initially at rest,move towards each other under the action of their internal attraction. If their speeds are $v$ and $2v$ at any instant,then the speed of the centre of mass of the system will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module