The electric field due to a short electric dipole at a distance $r$ on the axial line from its mid-point is $x$ times the electric field at a distance $2r$ on the equatorial line from the mid-point of the dipole. Then,the value of $x$ is

  • A
    $16$
  • B
    $9$
  • C
    $25$
  • D
    $36$

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Similar Questions

An electric dipole of moment $\vec{P}$ is placed in a uniform electric field $\vec{E}$ such that $\vec{P}$ points along $\vec{E}$. If the dipole is slightly rotated about an axis perpendicular to the plane containing $\vec{E}$ and $\vec{P}$ and passing through the centre of the dipole, the dipole executes simple harmonic motion. Consider $I$ to be the moment of inertia of the dipole about the axis of rotation. What is the time period of such oscillation?

Mention the directions of the electric field on the axis and on the equator of an electric dipole.

$A$ positive charge $Q$ is distributed uniformly over a circular ring of radius $R$. $A$ point particle having a mass $m$ and a negative charge $-q$ is placed on its axis at a distance $x$ from the centre. Assuming $x \ll R$,find the time period of oscillation of the particle,if it is released from there [neglect gravity].

Write the formulas for the electric field due to an electric dipole and the magnetic field due to a current-carrying loop at a point on their respective equatorial (bisector) lines at a distance $x$.

The angle between the dipole moment and electric field at any point on the equatorial plane is (in $^{\circ}$)

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