The effective resistance between A and B, if | vedclass

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(B) Due to the symmetry of the circuit about the horizontal axis, the potential at the top and bottom nodes is the same. Thus, no current flows throug

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$\frac{8}{3} R$

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(B) Due to the symmetry of the circuit about the horizontal axis, the potential at the top and bottom nodes is the same. Thus, no current flows through the vertical resistors, and they can be removed.After removing the vertical resistors, the circuit simplifies to three parallel branches between the two central nodes, each having a resistance of $R + R = 2R$.The equivalent resistance of these three parallel branches is given by $\frac{1}{R_{eq, parallel}} = \frac{1}{2R} + \frac{1}{2R} + \frac{1}{2R} = \frac{3}{2R}$, which gives $R_{eq, parallel} = \frac{2R}{3}$.Finally, this equivalent resistance is in series with the two resistors connected to terminals $A$ and $B$. Therefore, the total effective resistance is $R_{total} = R + \frac{2R}{3} + R = 2R + \frac{2R}{3} = \frac{8R}{3}$.

The effective resistance between $A$ and $B$, if the resistance of each resistor is $R$, will be

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