The domain of the function sqrt{log({x^2} - 6 | vedclass

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(C) The function $f(x) = \sqrt{\log({x^2} - 6x + 6)}$ is defined when $\log({x^2} - 6x + 6) \ge 0$.This implies ${x^2} - 6x + 6 \ge 10^0$,which simpli

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$(-\infty, 1] \cup [5, \infty)$

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(C) The function $f(x) = \sqrt{\log({x^2} - 6x + 6)}$ is defined when $\log({x^2} - 6x + 6) \ge 0$.This implies ${x^2} - 6x + 6 \ge 10^0$,which simplifies to ${x^2} - 6x + 6 \ge 1$.Rearranging the inequality,we get ${x^2} - 6x + 5 \ge 0$.Factoring the quadratic expression,we have $(x - 5)(x - 1) \ge 0$.Solving this inequality,we find that $x \le 1$ or $x \ge 5$.Thus,the domain of the function is $(-\infty, 1] \cup [5, \infty)$.

The domain of the function $\sqrt{\log({x^2} - 6x + 6)}$ is

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