The domain of f(x) = cos^{-1}[x] is,where [x] | vedclass

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(D) The function is defined as $f(x) = \cos^{-1}[x]$.We know that the domain of $\cos^{-1}(u)$ is $u \in [-1, 1]$.Therefore,for $\cos^{-1}[x]$ to be d

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$[-1, 2)$

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(D) The function is defined as $f(x) = \cos^{-1}[x]$.We know that the domain of $\cos^{-1}(u)$ is $u \in [-1, 1]$.Therefore,for $\cos^{-1}[x]$ to be defined,we must have $-1 \leq [x] \leq 1$.Since $[x]$ is the greatest integer function,the possible integer values for $[x]$ are $-1, 0, 1$.If $[x] = -1$,then $-1 \leq x If $[x] = 0$,then $0 \leq x If $[x] = 1$,then $1 \leq x Combining these intervals,we get $-1 \leq x Thus,the domain is $x \in [-1, 2)$.

The domain of $f(x) = \cos^{-1}[x]$ is,where $[x]$ denotes the greatest integer function.

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