The distance between the points A(0, 6) and B | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The distance formula between two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by:$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$Given points are $A(0,

Vedclass · Accepted Answer

$8$

Vedclass · Answer

(A) The distance formula between two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by:$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$Given points are $A(0, 6)$ and $B(0, -2)$.Here,$x_1 = 0, y_1 = 6$ and $x_2 = 0, y_2 = -2$.Substituting these values into the distance formula:$AB = \sqrt{(0 - 0)^2 + (-2 - 6)^2}$$AB = \sqrt{0^2 + (-8)^2}$$AB = \sqrt{64}$$AB = 8$Therefore,the distance between the points $A$ and $B$ is $8$ units.

The distance between the points $A(0, 6)$ and $B(0, -2)$ is

Similar Questions

Find the point on the $X$-axis which is equidistant from $(5, 4)$ and $(-2, 3)$.

$A(5,2), B(3,4)$ and $C(x, y)$ are collinear and $AB = BC$,then the coordinates of $C$ are...............

Show that,$(1, -3/2)$,$(-3, -7/2)$ and $(-4, -3/2)$ are the vertices of a right-angled triangle.

$A$ line intersects the $y$-axis and $x$-axis at the points $P$ and $Q$,respectively. If $(2, -5)$ is the mid-point of $PQ$,then the coordinates of $P$ and $Q$ are,respectively:

State whether the following statement is true or false. Justify your answer.
Point $P (-4, 2)$ lies on the line segment joining the points $A (-4, 6)$ and $B (-4, -6)$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module