The distance between the nearest node and antinode in a stationary wave is

Stationary waves can be produced in

Two waves are approaching each other with a velocity of $16 \ m/s$ and frequency $n$. The distance between two consecutive nodes is

Two progressive waves $Y_{1} = \sin 2\pi(\frac{t}{0.4} - \frac{x}{4})$ and $Y_{2} = \sin 2\pi(\frac{t}{0.4} + \frac{x}{4})$ superpose to form a standing wave. $x, Y_{1}$ and $Y_{2}$ are in $SI$ units. The amplitude of the particle at $x = 0.5 \ m$ is: (Given: $\sin 45^{\circ} = \cos 45^{\circ} = \frac{1}{\sqrt{2}}$)

What will be the phase difference of particles in successive intervals of stationary waves?

In a standing wave on a string: