The displacement y of a particle in a medium | vedclass

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(B) The standard wave equation is given by $y = A \sin(\omega t + kx + \phi)$.Comparing the given equation $y = 10^{-6} \sin(100t + 20x + \pi/4)$ with

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$5$

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(B) The standard wave equation is given by $y = A \sin(\omega t + kx + \phi)$.Comparing the given equation $y = 10^{-6} \sin(100t + 20x + \pi/4)$ with the standard equation,we get:Angular frequency $\omega = 100 \ rad/s$Wave number $k = 20 \ rad/m$The speed of the wave $v$ is given by the ratio of the coefficient of $t$ to the coefficient of $x$:$v = \frac{\omega}{k} = \frac{100}{20} = 5 \ m/s$.

The displacement $y$ of a particle in a medium can be expressed as: $y = 10^{-6} \sin(100t + 20x + \pi/4) \ m$,where $t$ is in seconds and $x$ is in meters. The speed of the wave is ... $m/s$.

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