The displacement of a body in $8\,s$ starting from rest with an acceleration of $20\,cm/s^2$ is:

The distance travelled by a particle is proportional to the square of time. Then,the particle travels with:

$A$ car moving along a straight highway with a speed of $126 \; km/h$ is brought to a stop within a distance of $200 \; m$. How long (in $seconds$) does it take for the car to stop?

If a particle moves according to the equation $v = at$,what distance will it cover in the first $4 \, s$ (in $a$)?

$A$ body is moving with a uniform velocity of $8\,m/s$. When the body just crosses another body,the second body starts from rest and moves with a uniform acceleration of $4\,m/s^2$. The time after which the two bodies meet will be $...........\,s$.

$A$ body starting from rest moves with constant acceleration. The ratio of distance covered by the body during the $5^{th}$ second to that covered in $5$ seconds is