The dimensions of a field are 20 text{ m} by | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Volume of earth removed $= 10 	ext{ m} 	imes 4.5 	ext{ m} 	imes 3 	ext{ m} = 135 	ext{ m}^3$.Total area of the field $= 20 	ext{ m} 	imes

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(D) Volume of earth removed $= 10 	ext{ m} 	imes 4.5 	ext{ m} 	imes 3 	ext{ m} = 135 	ext{ m}^3$.Total area of the field $= 20 	ext{ m} 	imes 9 	ext{ m} = 180 	ext{ m}^2$.Area of the pit $= 10 	ext{ m} 	imes 4.5 	ext{ m} = 45 	ext{ m}^2$.Remaining area of the field $= 180 	ext{ m}^2 - 45 	ext{ m}^2 = 135 	ext{ m}^2$.Let the rise in the height of the field be $h 	ext{ m}$.Since the earth removed is spread over the remaining area,the volume of the earth removed equals the volume of the raised layer:$135 	ext{ m}^2 	imes h 	ext{ m} = 135 	ext{ m}^3$.Solving for $h$:$h = \frac{135}{135} = 1 	ext{ m}$.Therefore,the rise in the height of the field is $1 	ext{ m}$.

Similar Questions

$ABCD$ is a cyclic quadrilateral. $AB$ and $DC$ when produced meet at $P$. If $PA = 8 \ cm$,$PB = 6 \ cm$,and $PC = 4 \ cm$,then the length (in $cm$) of $PD$ is:

The base of a triangular field is three times its altitude. If the cost of cultivating the field at $50$ per hectare is $Rs. 675$,then what are its base and height?

The sum of the circumference of a circle and the perimeter of a square is equal to $272 \, cm$. The diameter of the circle is $56 \, cm$. What is the sum of the areas of the circle and the square? (in $cm^2$)

The side of a square exceeds the side of another square by $4\, cm$ and the sum of the areas of the two squares is $400\, cm^2$. The dimensions of the squares are?

Vedclass Test Series

Exam Paper Generator

Online Exam Module