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(D) The dimension of stopping potential $V_{0}$ is equivalent to the dimension of potential difference,which is $\frac{	ext{Work}}{	ext{Charge}} = \

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$h^{0} c^{5} G^{-1} A^{-1}$

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(D) The dimension of stopping potential $V_{0}$ is equivalent to the dimension of potential difference,which is $\frac{	ext{Work}}{	ext{Charge}} = \frac{ML^{2}T^{-2}}{AT} = ML^{2}T^{-3}A^{-1}$.Let $V_{0} = h^{x} c^{y} G^{z} A^{w}$.Substituting the dimensions: $[ML^{2}T^{-3}A^{-1}] = [ML^{2}T^{-1}]^{x} [LT^{-1}]^{y} [M^{-1}L^{3}T^{-2}]^{z} [A]^{w}$.Equating the powers of $A$: $w = -1$.Equating the powers of $M$: $x - z = 1$.Equating the powers of $L$: $2x + y + 3z = 2$.Equating the powers of $T$: $-x - y - 2z = -3$.Solving these equations: From $x - z = 1$,we get $x = 1 + z$.Adding the equations for $L$ and $T$: $(2x + y + 3z) + (-x - y - 2z) = 2 + (-3) \Rightarrow x + z = -1$.Now we have $x - z = 1$ and $x + z = -1$. Adding them gives $2x = 0 \Rightarrow x = 0$. Then $z = -1$.Substituting $x=0$ and $z=-1$ into $2x + y + 3z = 2$: $0 + y - 3 = 2 \Rightarrow y = 5$.Thus,$V_{0} = h^{0} c^{5} G^{-1} A^{-1}$.

The dimension of stopping potential $V_{0}$ in the photoelectric effect in terms of Planck's constant $h$,speed of light $c$,gravitational constant $G$,and ampere $A$ is:

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