The digit in the unit's place in the square r | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) To find the unit's digit of the square root of $15876$,we observe the unit's digit of the number itself,which is $6$.If a perfect square ends in $

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(C) To find the unit's digit of the square root of $15876$,we observe the unit's digit of the number itself,which is $6$.If a perfect square ends in $6$,its square root must end in either $4$ or $6$ (since $4^2 = 16$ and $6^2 = 36$).We can estimate the square root: $100^2 = 10000$ and $200^2 = 40000$.Since $15876$ is between $100^2$ and $200^2$,the square root is between $100$ and $200$.Checking $120^2 = 14400$ and $130^2 = 16900$.Since $15876$ is between $14400$ and $16900$,the square root is between $120$ and $130$.The possible values are $124$ or $126$.Calculating $126^2 = 15876$.Therefore,the unit's digit is $6$.

The digit in the unit's place in the square root of $15876$ is

Similar Questions

What number should be divided by $\sqrt{0.25}$ to give the result as $25$?

$\sqrt{11449} \times \sqrt{6241} - (54)^{2} = \sqrt{?} + (74)^{2}$

The square root of $\frac{(0.75)^{3}}{1-0.75}+\left(0.75+(0.75)^{2}+1\right)$ is

Find the smallest number,which,when added to $3579$ gives a perfect square.

$\left(\sqrt{3}-\frac{1}{\sqrt{3}}\right)^{2}$ simplifies to

Vedclass Test Series

Exam Paper Generator

Online Exam Module