The diagram shows a force-extension graph for | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The graph shows a hysteresis loop for a rubber band. $(I)$ The graph is a force-extension graph,not a force-compression graph. Therefore,we cannot

Vedclass · Accepted Answer

$III$ only

Vedclass · Answer

(A) The graph shows a hysteresis loop for a rubber band. $(I)$ The graph is a force-extension graph,not a force-compression graph. Therefore,we cannot deduce anything about compression from this graph. $(II)$ The graph starts at the origin $(0,0)$ and returns to the origin $(0,0)$ after the cycle is completed,which indicates that the rubber band returns to its original length. Thus,statement $(II)$ is incorrect. $(III)$ The area enclosed by the hysteresis loop represents the energy dissipated as heat during one complete cycle of stretching and unstretching. Therefore,the rubber band will get heated. Thus,statement $(III)$ is correct. Hence,only statement $(III)$ can be deduced from the graph.

Similar Questions

The random variable $X$ takes the values $1, 2, 3, \ldots, m$. If $P(X=n) = \frac{1}{m}$ for each $n$,then the variance of $X$ is

If $f(x) = x^5 - 5x^4 + 5x^3 - 10$ has local maximum and minimum at $x = p$ and $x = q$,respectively,then $(p, q)$ equals

If $\int \frac{d x}{x(\log x-2)(\log x-3)}=I+C$,then $I$ is equal to

If $x=\log _{0.1} 0.001$ and $y=\log _9 81$,then $\sqrt{x-2 \sqrt{y}}$ is equal to

$A$ line is at a constant distance $c$ from the origin and meets the coordinate axes in $A$ and $B$. The locus of the centre of the circle passing through $O, A, B$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module