The density of water is 1 , g/mL. What is the | vedclass

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(D) The molar mass of water $(H_2O)$ is $18 \, g/mol$.Given density of water is $1 \, g/mL$,so $18 \, g$ of water occupies $18 \, mL$.Since $1 \, mol$

Vedclass · Accepted Answer

$2.99 	imes 10^{-23} \, mL$

Vedclass · Answer

(D) The molar mass of water $(H_2O)$ is $18 \, g/mol$.Given density of water is $1 \, g/mL$,so $18 \, g$ of water occupies $18 \, mL$.Since $1 \, mol$ of water contains $6.022 	imes 10^{23}$ molecules,the volume of $6.022 	imes 10^{23}$ molecules is $18 \, mL$.Therefore,the volume of $1$ molecule of water is $\frac{18 \, mL}{6.022 	imes 10^{23}} \approx 2.99 	imes 10^{-23} \, mL$.

The density of water is $1 \, g/mL$. What is the volume occupied by $1$ molecule of water :-

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