The density of a liquid is 1.5 , g/mL. There | vedclass

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(C) Volume of $1 \, drop = \frac{5 \, mL}{50} = 0.1 \, mL$. Mass of $1 \, drop = 	ext{density} 	imes 	ext{volume} = 1.5 \, g/mL 	imes 0.1 \, mL =

Vedclass · Accepted Answer

$9 	imes 10^{20}$

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(C) Volume of $1 \, drop = \frac{5 \, mL}{50} = 0.1 \, mL$. Mass of $1 \, drop = 	ext{density} 	imes 	ext{volume} = 1.5 \, g/mL 	imes 0.1 \, mL = 0.15 \, g$. Number of moles in $1 \, drop = \frac{	ext{mass}}{	ext{molecular weight}} = \frac{0.15 \, g}{100 \, g/mol} = 1.5 	imes 10^{-3} \, mol$. Number of molecules in $1 \, drop = 	ext{moles} 	imes N_A = 1.5 	imes 10^{-3} 	imes 6.022 	imes 10^{23} \approx 9.033 	imes 10^{20} \approx 9 	imes 10^{20}$.

The density of a liquid is $1.5 \, g/mL$. There are $50 \, drops$ in $5 \, mL$. The number of molecules in $1 \, drop$ is (molecular weight of liquid is $100$).

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