The densities of a liquid at 0^{circ} C and 1 | vedclass

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(B) Density at $0^{\circ} C$,$ho_0 = 1.0127$.Density at $100^{\circ} C$,$ho_{100} = 1$.Coefficient of real expansion of liquid,$\gamma_{	ext{real

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$\frac{3}{1.01}$

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(B) Density at $0^{\circ} C$,$ho_0 = 1.0127$.Density at $100^{\circ} C$,$ho_{100} = 1$.Coefficient of real expansion of liquid,$\gamma_{	ext{real}} = \frac{ho_0 - ho_{100}}{ho_{100} 	imes \Delta t} = \frac{1.0127 - 1}{1 	imes 100} = 1.27 	imes 10^{-4} /^{\circ} C$.Coefficient of volume expansion of glass,$\gamma_g = 3 \alpha = 3 	imes 9 	imes 10^{-6} = 2.7 	imes 10^{-5} = 0.27 	imes 10^{-4} /^{\circ} C$.Coefficient of apparent expansion,$\gamma_{	ext{app}} = \gamma_{	ext{real}} - \gamma_g = 1.27 	imes 10^{-4} - 0.27 	imes 10^{-4} = 1 	imes 10^{-4} /^{\circ} C$.The mass expelled is given by $\Delta m = m_0 	imes \gamma_{	ext{app}} 	imes \Delta t$ (approximately,for small changes) or using the relation $\frac{m_1}{m_2} = 1 + \gamma_{	ext{app}} \Delta t$.Here,$m_1 = 300 \ g$.$\frac{300}{m_2} = 1 + (10^{-4} 	imes 100) = 1 + 0.01 = 1.01$.$m_2 = \frac{300}{1.01}$.Mass expelled $= m_1 - m_2 = 300 - \frac{300}{1.01} = 300 \left(1 - \frac{1}{1.01}ight) = 300 \left(\frac{0.01}{1.01}ight) = \frac{3}{1.01} \ g$.

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