The degree of hydrolysis of a salt of weak ac | vedclass

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(A) For a salt of a weak acid and a weak base,the hydrolysis constant $K_h$ is given by the expression: $K_h = \frac{h^2}{(1-h)^2}$,where $h$ is the d

Vedclass · Accepted Answer

$50$

Vedclass · Answer

(A) For a salt of a weak acid and a weak base,the hydrolysis constant $K_h$ is given by the expression: $K_h = \frac{h^2}{(1-h)^2}$,where $h$ is the degree of hydrolysis.Since $K_h$ is a constant at a given temperature,the degree of hydrolysis $h$ is independent of the concentration of the salt solution.Therefore,if the degree of hydrolysis is $50 \%$ at $0.1 \, M$,it will remain $50 \%$ at $0.2 \, M$ as well.

The degree of hydrolysis of a salt of weak acid and weak base in its $0.1 \, M$ solution is found to be $50 \%$. If the molarity of the solution is $0.2 \, M$,the percentage hydrolysis of the salt should be $...... \%$.

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