The degree of dissociation of a first-order r | vedclass

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Question

(D) For a first-order reaction,the integrated rate equation is given by: $\ln \frac{a}{a-x} = kt$ Rearranging the equation: $\frac{a-x}{a} = e^{-kt}$

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$1-e^{-kt}$

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(D) For a first-order reaction,the integrated rate equation is given by: $\ln \frac{a}{a-x} = kt$ Rearranging the equation: $\frac{a-x}{a} = e^{-kt}$ This can be written as: $1 - \frac{x}{a} = e^{-kt}$ The degree of dissociation,denoted by $\alpha$,is defined as the fraction of the initial concentration that has reacted,i.e.,$\alpha = \frac{x}{a}$. Substituting this into the equation: $1 - \alpha = e^{-kt}$ Therefore,$\alpha = 1 - e^{-kt}$

The degree of dissociation of a first-order reaction is

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