(B) For the equilibrium $PCl_5 \rightleftharpoons PCl_3 + Cl_2$,the equilibrium constant $K_p$ is given by:$K_p = \frac{\alpha^2}{1 - \alpha^2} P$Give

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$\alpha \propto \frac{1}{\sqrt{P}}$

(B) For the equilibrium $PCl_5 \rightleftharpoons PCl_3 + Cl_2$,the equilibrium constant $K_p$ is given by:$K_p = \frac{\alpha^2}{1 - \alpha^2} P$Given $\alpha Thus,$K_p \approx \alpha^2 P$.Rearranging for $\alpha$,we get $\alpha^2 \approx \frac{K_p}{P}$,which implies $\alpha \approx \sqrt{\frac{K_p}{P}}$.Therefore,$\alpha \propto \frac{1}{\sqrt{P}}$.

Class 11 Chemistry 6-1.Equilibrium (Chemical Equilibrium)Degree of dissociation and Vapour density

Medium

The degree of dissociation of $PCl_5$ $(\alpha)$ obeying the equilibrium,$PCl_5 \rightleftharpoons PCl_3 + Cl_2$,is approximately related to the pressure at equilibrium by (given $\alpha << 1$):

A
$\alpha \propto P$
B
$\alpha \propto \frac{1}{\sqrt{P}}$
C
$\alpha \propto \frac{1}{P^2}$
D
$\alpha \propto \frac{1}{P^4}$

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6-1.Equilibrium (Chemical Equilibrium)

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Degree of dissociation and Vapour density

At $444\,^oC$,the equilibrium constant $K$ for the reaction $2AB_{(g)} \rightleftharpoons A_{2(g)} + B_{2(g)}$ is $\frac{1}{64}$. The degree of dissociation of $AB$ will be .....$\%$

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For the equilibrium reaction $N_2O_{4(g)} \rightleftharpoons 2NO_{2(g)}$,the value of $K_p$ is $2$. Calculate the percentage dissociation of $N_2O_{4(g)}$ at a total pressure of $0.5 \ atm$. (in $\%$)

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For completely dissociated $NH_4Cl$,the vapour density is ........

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In a closed vessel,the dissociation of phosphorus pentachloride occurs as: $PCl_5(g) \rightleftharpoons PCl_3(g) + Cl_2(g)$. If the total pressure at equilibrium is $P$ and the degree of dissociation of $PCl_5$ is $x$,then the partial pressure of $PCl_3$ will be:

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At $T \, ^\circ C$,the vapour density of $PCl_5$ is $104.25$. The degree of dissociation of $PCl_5$ is ....$\%$

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The degree of dissociation of $PCl_5$ $(\alpha)$ obeying the equilibrium,$PCl_5 \rightleftharpoons PCl_3 + Cl_2$,is approximately related to the pressure at equilibrium by (given $\alpha << 1$):

Similar Questions

At $444\,^oC$,the equilibrium constant $K$ for the reaction $2AB_{(g)} \rightleftharpoons A_{2(g)} + B_{2(g)}$ is $\frac{1}{64}$. The degree of dissociation of $AB$ will be .....$\%$

For the equilibrium reaction $N_2O_{4(g)} \rightleftharpoons 2NO_{2(g)}$,the value of $K_p$ is $2$. Calculate the percentage dissociation of $N_2O_{4(g)}$ at a total pressure of $0.5 \ atm$. (in $\%$)

For completely dissociated $NH_4Cl$,the vapour density is ........

In a closed vessel,the dissociation of phosphorus pentachloride occurs as: $PCl_5(g) \rightleftharpoons PCl_3(g) + Cl_2(g)$. If the total pressure at equilibrium is $P$ and the degree of dissociation of $PCl_5$ is $x$,then the partial pressure of $PCl_3$ will be:

At $T \, ^\circ C$,the vapour density of $PCl_5$ is $104.25$. The degree of dissociation of $PCl_5$ is ....$\%$

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