The degree and order of the differential equa | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The general equation of a parabola with its axis as the $x$-axis is given by $y^2 = 4a(x - h)$,where $a$ and $h$ are arbitrary constants.Since the

Vedclass · Accepted Answer

$1, 2$

Vedclass · Answer

(B) The general equation of a parabola with its axis as the $x$-axis is given by $y^2 = 4a(x - h)$,where $a$ and $h$ are arbitrary constants.Since there are two arbitrary constants,we differentiate the equation twice.First derivative: $2y y_1 = 4a$,which simplifies to $y y_1 = 2a$.Second derivative: $y_1^2 + y y_2 = 0$.In the differential equation $y_2 y + y_1^2 = 0$,the highest order derivative is $y_2$,so the order is $2$.The power of the highest order derivative $y_2$ is $1$,so the degree is $1$.Therefore,the degree is $1$ and the order is $2$.

The degree and order of the differential equation of the family of all parabolas whose axis is the $x$-axis,are respectively

Similar Questions

According to the kinetic theory of gases,when two molecules of gas collide with each other,then:

If the lines,joining the origin to the points of intersection of the curve $2x^2 - 2xy + 3y^2 + 2x - y - 1 = 0$ and the line $x + 2y = k$,are at right angles,then $k^2$ equals

The area (in sq units) of the quadrilateral formed by two pairs of lines $\lambda^2 x^2 - m^2 y^2 - n(\lambda x + m y) = 0$ and $\lambda^2 x^2 - m^2 y^2 + n(\lambda x + m y) = 0$ is:

Which of the following is non-ionizable?

An infinitely long thin straight wire has a uniform linear charge density of $\frac{1}{3} ~Cm^{-1}$. The magnitude of the electric field intensity at a point $18 ~cm$ away is (given $\varepsilon_0 = 8.85 \times 10^{-12} ~C^2 N^{-1} m^{-2}$):

Vedclass Test Series

Exam Paper Generator

Online Exam Module